Bismillahir Rahmanir Raheem.
If x=y then is a+g=y−x wrong?
What about x=y=0?
(0+0)/2 + sqrt(0*0) = 0-0.
Tanvir Zawad
Search found 3 matches
- Fri Aug 12, 2011 1:30 am
- Forum: Divisional Math Olympiad
- Topic: AM-GM problem
- Replies: 11
- Views: 7423
- Fri Aug 12, 2011 12:37 am
- Forum: College / University Level
- Topic: a problem from IUMO 09
- Replies: 11
- Views: 16844
Re: a problem from IUMO 09
I defined n to be a number whose last 1000 digits are only 1 or 2.
Note that, asking whether there exists any 2^X such that its right 1000 digits are only 1 or 2 is equivalent to asking whether log2 (n) exists.
log2 (n) exists, and hence there exists such 2^X.
Tanvir Zawad
Note that, asking whether there exists any 2^X such that its right 1000 digits are only 1 or 2 is equivalent to asking whether log2 (n) exists.
log2 (n) exists, and hence there exists such 2^X.
Tanvir Zawad
- Sat Jul 09, 2011 4:23 am
- Forum: College / University Level
- Topic: a problem from IUMO 09
- Replies: 11
- Views: 16844
Re: a problem from IUMO 09
let,
2^x=...(thousand 1 or 2)=n.
=> log2 (2^x)=log2 (n).
=> x=m, where m=log2 (n).
Now, since m is a real number, there exists such x. [Proved]
Alhamdulillah!
Tanvir Zawad
2^x=...(thousand 1 or 2)=n.
=> log2 (2^x)=log2 (n).
=> x=m, where m=log2 (n).
Now, since m is a real number, there exists such x. [Proved]
Alhamdulillah!
Tanvir Zawad