Search found 6 matches
- Mon Jan 14, 2013 8:02 pm
- Forum: Junior: Solved
- Topic: Dhaka Junior 2011/5
- Replies: 5
- Views: 11115
Re: Dhaka Junior 2011/5
Four digit palindrome number should be like ABBA.If u reverse it u will get also ABBA.At first we will count how many numbers are palindrome.It is enough to count AB.SO we will get the result 9o.Then the ans 10000-90=9910 4 digit number starts from 1000 so there are 9000 4 digit numbers therefore t...
- Mon Jan 14, 2013 7:51 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National 2012: Junior 6
- Replies: 4
- Views: 4837
Re: BdMO National 2012: Junior 6
The distance from B to the point on the circle that is furthest from B is 9.8 cm .
- Sun Jan 13, 2013 4:49 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Primary 2011/3
- Replies: 2
- Views: 3127
Re: BdMO National Primary 2011/3
51 balls is the answer
- Thu Jan 10, 2013 7:27 pm
- Forum: Physics
- Topic: Change of temperature by adding water
- Replies: 4
- Views: 4657
Change of temperature by adding water
Some hot water was added to three times its mass of water at 100 C and the resulting temperature was 200 C. What was the temperature of the hot water?
From ctg ques 2013
Pls explain the answer
From ctg ques 2013
Pls explain the answer
- Thu Jan 10, 2013 5:10 pm
- Forum: Junior: Solved
- Topic: Dhaka Junior 2011/9
- Replies: 7
- Views: 13465
Re: Dhaka Junior 2011/9
Can u draw it on a paper and then upload the image with positions of all e points? I cant understand the position of enafistiham wrote:$BD=2$
$DE=DO+OE=DO+DO=AC=3$
$BE^2=BD^2+DE^2=13$
- Thu Jan 10, 2013 4:42 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National 2012: Junior 5
- Replies: 5
- Views: 5828
Re: BdMO National 2012: Junior 5
I could solve the 1st part only....can anyone explain the another one..... Here is my ans ( I'm not sure wheter i'm correct ) :?: 2nd Part $\angle ACB = 30^{\circ}$ $\angle ABC = 90^{\circ}$ ( Since it is a right angled triangle ) $\angle BAC + 30^{\circ} + 90^{\circ} = 180^{\circ}$ $\angle BAC= 60...