Search found 4 matches
- Sat Nov 14, 2015 3:43 pm
- Forum: Combinatorics
- Topic: A probability problem
- Replies: 4
- Views: 3993
Re: A probability problem
I see my mistake. $\frac{11 + 3(11\times10) + 11\times10\times9 + 3(\frac{11\times10\times9}{2!}) + \frac{11\times10\times9\times8}{2!} + 2(\frac{11\times10\times9\times8}{3!}) + \frac{11\times10\times9\times8\times7}{2!\,3!} + \frac{11\times10\times9\times8\times7}{4!} + \frac{11\times10\times9\tim...
- Mon Jul 27, 2015 12:51 am
- Forum: Combinatorics
- Topic: A probability problem
- Replies: 4
- Views: 3993
Re: A probability problem
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
10টি ভিন্ন অক্ষর নেওয়া যেতে পারে $\binom{26}{10}$ভাবে।
$\frac{\binom{26}{10} - (\binom{24}{8} + \binom{23}{8} + \binom{22}{8} + ... + \binom{8}{8})}{\binom{26}{10}}=\frac{8}{13}$
সমাধান ভুল হতে পারে।
10টি ভিন্ন অক্ষর নেওয়া যেতে পারে $\binom{26}{10}$ভাবে।
$\frac{\binom{26}{10} - (\binom{24}{8} + \binom{23}{8} + \binom{22}{8} + ... + \binom{8}{8})}{\binom{26}{10}}=\frac{8}{13}$
সমাধান ভুল হতে পারে।
- Mon Mar 09, 2015 1:42 am
- Forum: Higher Secondary Level
- Topic: Need help
- Replies: 3
- Views: 4027
Re: Need help
Wow, I am impressed. Thank you.
- Sat Dec 20, 2014 1:54 am
- Forum: Higher Secondary Level
- Topic: Need help
- Replies: 3
- Views: 4027
Need help
How to prove that the product of n numbers is maximum when and only when all the numbers are equal provided that their sum is a constant? (n is an arbitrary natural number)