## Search found 3 matches

Tue Sep 12, 2017 7:41 pm
Forum: Asian Pacific Math Olympiad (APMO)
Topic: APMO 2017 P2
Replies: 2
Views: 841

### Re: APMO 2017 P2

Let $M$ and $N$ be the midpoints of $AB$ and $AC$.$MN$ meets $DC$ at $X$.Then $\angle AMX=\angle ABC=\angle ADX$.So $A$,$M$,$D$,$X$ are cyclic.Then $\angle NXC=\angle MXD=\angle MAD=\angle DAC=\angle AZN=\angle CZN$ implies $Z$,$N$,$C$,$X$ are cyclic so $\angle CXZ=\angle DXZ=90$,$\angle DAZ=90$. So...
Wed Mar 29, 2017 4:34 pm
Forum: National Math Camp
Topic: The Gonit IshChool Project - Beta
Replies: 28
Views: 3332

### Re: The Gonit IshChool Project - Beta

Name you'd like to be called: Saad
Course you want to learn: Functional Equations and Number Theory Problem solving.
Preferred methods of communication (Forum, Messenger, Telegram, etc.):Telegram,Messenger.
Do you want to take lessons through PMs or Public?: Public
Thu Jan 19, 2017 6:46 pm
Forum: Geometry
Topic: IGO 2016 Medium/5
Replies: 1
Views: 561

### Re: IGO 2016 Medium/5

[AST: Alternate Segment Theorem] We assume that, WLOG radius of $\omega$ is less than radius of $\omega'$(equality case is trivial). Let $P$ be the midpoint of $\widehat{EF}$ not containing $B$ of $\odot BEF$, thus $BP$ is the angle bisector of $\angle EBF$. Let the tangent at $P$ to $BEF$ intersect...