Search found 5 matches
- Wed Apr 10, 2019 11:24 am
- Forum: Divisional Math Olympiad
- Topic: Mymensingh higher secondary 2013#1
- Replies: 3
- Views: 11924
Re: Mymensingh higher secondary 2013#1
Hint Easy algebra Answer $22$ How can this be 22? I think this should be 13! Cuz.. If nonte+fonte=25 or, nonte=25-fonte.........................(1) and nut+boltu=40...........................(2) Here, nut=nonte+2 [at least] So, So, equation 2 stands, nut+boltu=40 or, nonte+2+boltu=40 or, 25-fonte+2...
- Wed Apr 10, 2019 10:55 am
- Forum: Divisional Math Olympiad
- Topic: Rajshahi Higher Secondary 2017 P4
- Replies: 1
- Views: 9505
Re: Rajshahi Higher Secondary 2017 P4
In case of 60 persons causing traffic jams, people with private cars that cause this are 40 in number.
In case of 1 person causing traffic jam, people with private cars that cause this are 40/60 in number.
=2/3 no. of people.
So the probability must be= 2/(3*40) =1/60 [ANS]
In case of 1 person causing traffic jam, people with private cars that cause this are 40/60 in number.
=2/3 no. of people.
So the probability must be= 2/(3*40) =1/60 [ANS]
- Wed Apr 10, 2019 10:47 am
- Forum: Divisional Math Olympiad
- Topic: Rajshahi Higher Secondary 2017 P2
- Replies: 1
- Views: 9585
Re: Rajshahi Higher Secondary 2017 P2
ABOLTABOL(2017) is equals to HABIZABI(2048) or HABIZABI(2^11) which is equals to 11 So ABOLTABOL(ABOLTABOL(2017))=ABOLTABOL(11) Now, ABOLTABOL(11)=HABIZABI(42) which is =2 [Since 42 is not a power of 2] So, the question can be simplified as.. HABIZABI(HABIZABI(2^1)) =HABIZABI(1) =HABIZABI(2^0) =0 [A...
- Wed Jan 16, 2019 11:08 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National 2013: Primary 6
- Replies: 3
- Views: 4579
Re: BdMO National 2013: Primary 6
The condition will be met, when the corners will perfectly fit with each other. so, the sum of the corner's angle must be 360. the angle of a vertex of an 'n-gon' is 180(n-2)/n. so, 360/{180(n-2)/n} must be a natural number. let, 360/{180(n-2)/n}=k , where k is a natural number. This implies, 2n/(n-...
- Wed Jan 16, 2019 10:40 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National 2013: Primary 4
- Replies: 3
- Views: 4121
Re: BdMO National 2013: Primary 4
Let, in first row, the number of keys is '2k+1' (cuz excluding 1 key, if there are k no. of keys in one side, then total no. of keys is 2k+1) in second row, the number of keys is '2n+1' in third row, the number of keys is '2m+1', /*k,m,n are natural numbers*/ then 2k+1+2m+1+2n+1=26 which implies, (k...