I used angle measuring instrument to measure them.
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- Mon Mar 11, 2019 11:38 pm
- Forum: Junior Level
- Topic: BDMO 2016 Regional
- Replies: 17
- Views: 107405
Re: BDMO 2016 Regional
- Mon Mar 11, 2019 11:36 pm
- Forum: Junior Level
- Topic: BDMO 2016 Regional
- Replies: 17
- Views: 107405
Re: BDMO 2016 Regional
Yes,Solution is not right.
- Sun Mar 10, 2019 11:53 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2019/6
- Replies: 2
- Views: 8788
Re: BdMO National Higher Secondary 2019/6
@Jim huge solution.
I also solved it after the olympiad.
I posted the problem @ AoPS.
You can see that solution too.
I also solved it after the olympiad.
![Crying or Very Sad :cry:](./images/smilies/icon_cry.gif)
![Crying or Very Sad :cry:](./images/smilies/icon_cry.gif)
![Crying or Very Sad :cry:](./images/smilies/icon_cry.gif)
I posted the problem @ AoPS.
You can see that solution too.
- Sun Mar 10, 2019 11:03 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Secondary 2007#9
- Replies: 2
- Views: 8035
Re: BdMO National Secondary 2007#9
Answer: $b=\dfrac {23}{4},c=\dfrac {17}{4}$ Solution: $x^2+3x-4=0\Rightarrow x^2+4x-x-4=0\Rightarrow(x+4)(x-1)=0\Rightarrow x=-4,1$ The given equation $x^3+bx^2+cx+11=0$ Let $x=x_1,x_2,x_3$ So,$x_1=-4,x_2=1$ From the equation $x_1\times x_2\times x_3= 11\Rightarrow x_3=\dfrac {11}{-4}$ Hence,$b=-(-...
- Sun Mar 10, 2019 10:24 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Secondary 2010#8
- Replies: 1
- Views: 7576
- Sun Mar 10, 2019 10:21 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Higher Secondary 2010/4
- Replies: 2
- Views: 9252
Re: BdMO National Higher Secondary 2010/4
I have found a solution here.
- Sun Mar 10, 2019 10:16 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Secondary 2007/1
- Replies: 2
- Views: 8469
Re: BdMO National Secondary 2007/1
Same kind of problem.
Solution
- Sun Mar 10, 2019 9:05 pm
- Forum: News / Announcements
- Topic: Attention: BdMO resource section: New Project
- Replies: 16
- Views: 39954
- Sun Mar 10, 2019 8:27 pm
- Forum: Divisional Math Olympiad
- Topic: BDMO REGIONAL 2015
- Replies: 4
- Views: 18991
Re: BDMO REGIONAL 2015
I have understood the reason.
Correct answer is $\fbox 4$
This problem is from BdMO Regional 2015 Mymensingh.
- Sun Mar 10, 2019 7:33 pm
- Forum: Junior Level
- Topic: BDMO 2016 Regional
- Replies: 17
- Views: 107405
Re: BDMO 2016 Regional
Once upon a time,I tried a lot to solve this problem but didn't find the answer.I think this is not a very tough problem. If you connect the centers you will get a rhombus My solution is wrong. I am not sure about the main solution. For posting BdMO Regional problems use the subforum named Divisiona...