Search found 38 matches
- Fri Apr 26, 2019 4:35 pm
- Forum: Physics
- Topic: BdPhO Regional (Dhaka-South) Higher Secondary 2019/1
- Replies: 0
- Views: 46005
BdPhO Regional (Dhaka-South) Higher Secondary 2019/1
BdPhO Regional (Dhaka-South) Higher Secondary 2019(1).png A coherent beam of monochromatic light of wavelength $500$ $nm$ is directed towards two thin slits separated by a distance of $1$ $mm$. If the screen covers an angular region of $60˚$, as shown in the figure, approximately how many bright in...
- Thu Apr 25, 2019 9:33 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Problem Collection(2011-2018)
- Replies: 3
- Views: 16354
Re: BdMO National Problem Collection(2011-2018)
Thank you very much. That'll be really very useful for us.
- Thu Apr 25, 2019 9:24 pm
- Forum: Physics
- Topic: BdPhO Regional (Dhaka-South) Secondary 2019/6
- Replies: 1
- Views: 13722
Re: BdPhO Regional (Dhaka-South) Secondary 2019/6
Given, $n(y)=ky,$ $where$ $0<y<h$. Suppose that, $y_1<y_2<y_3$. Then, $n_1<n_2<n_3$, Hence, $sin θ_1>sinθ_2>sinθ_3$ (Snell's law) $⇒$ $θ_1>θ_2>θ_3$ BdPhO Regional (Dhaka-South) Secondary 2019(6S).png By Snell's law, $\dfrac{n_1}{n_2}=\dfrac{sinθ_2}{sinθ_1}$ $∴$ $n_1 sinθ_1=n_2 sinθ_2=n_3 sinθ_3=...=...
- Thu Apr 25, 2019 8:19 pm
- Forum: National Math Olympiad (BdMO)
- Topic: BdMO National Secondary 2018:Full Solution
- Replies: 4
- Views: 23051
Re: BdMO National Secondary 2018:Full Solution
How did you know about that?samiul_samin wrote: ↑Mon Feb 25, 2019 1:45 pmAll solution of the problems of BdMO National Secondary $2018$ are available here.
Made by Soyeb Pervez Jim
- Wed Apr 24, 2019 8:29 pm
- Forum: Physics
- Topic: BdPhO Regional (Dhaka-South) Secondary 2019/7
- Replies: 1
- Views: 13329
Re: BdPhO Regional (Dhaka-South) Secondary 2019/7
Let the point where the water slide touches the ground be $D$. At point $D$, $v_0^2=2gH$. At point $B$, $v^2=v_0^2-2gh=2g(H-h)$. Now, Azmain should travel on PROJECTILE MOTION .(If you have no idea about projectile motion, you can click on the link for easy explanation.) Velocity among $X$ axis, $v_...
- Wed Apr 24, 2019 5:29 pm
- Forum: Physics
- Topic: BdPhO Regional (Dhaka-South) Secondary 2019/4
- Replies: 1
- Views: 13291
Re: BdPhO Regional (Dhaka-South) Secondary 2019/4
As the system is isolated, energy cannot enter or get out from it. The ball is released from height, $H$. When it touches the ground, the kinetic energy converts into sound and thermal energy. I mean, $Kinetic$ $Energy$ $=$ $Sound$ $Energy$ $+$ $Thermal$ $Energy$ But in fact, the sound energy is neg...
- Wed Apr 24, 2019 4:59 pm
- Forum: Secondary Level
- Topic: 0^0=1!
- Replies: 1
- Views: 11768
0^0=1!
Yeah, that's not any joke! I'm really gonna prove that!
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
0^0=1!
Yeah, that's not any joke! I'm really gonna prove that!
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
- Wed Apr 24, 2019 1:44 pm
- Forum: Physics
- Topic: BdPhO Regional (Dhaka-South) Secondary 2019/1
- Replies: 1
- Views: 13235
Re: BdPhO Regional (Dhaka-South) Secondary 2019/1
Firstly let's make the picture easy. BdPhO Regional (Dhaka-South) Secondary 2019(1S).png Here, $R_1=2 Ω, R_2=3 Ω, R_3=1 Ω, R_4=4 Ω, R_5=5 Ω$ Current cannot flow throw voltmeter, so $R_5$ is useless. Equivalent Resistance, $R=\dfrac{(R_1+R_2)(R_3+R_4)}{R_1+R_2+R_3+R_4}=2.5Ω$ $∴$ $I=\dfrac{V}{R}=4$ $A...
- Wed Apr 24, 2019 12:43 pm
- Forum: Social Lounge
- Topic: Share your AoPS id name
- Replies: 8
- Views: 36554
Re: Sharing my AoPS id name
My AoPS ID is SINAN_EXPERT.