$ABCD$ is a parallelogram where $\angle{ACB}=80^{\circ} $ $\angle{ACD}=20^{\circ} $ ,$P$
is a point on $AC$ such that,$\angle{ABP}=20^{\circ} $ and $Q$ is a point on $AB$ such that $\angle{ACQ}=30^{\circ} $ .Find the magnitude of the angle determined by the lines $CD$ and $PQ$.
BdMO National Junior 2015#6
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Re: BdMO National Junior 2015#6
Hint
Answer
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