BdMO National Secondary 2015#5

Discussion on Bangladesh Mathematical Olympiad (BdMO) National
samiul_samin
Posts:1007
Joined:Sat Dec 09, 2017 1:32 pm
BdMO National Secondary 2015#5

Unread post by samiul_samin » Wed Feb 20, 2019 8:44 pm

A tetrahedron is a polyhedron composed of four triangular faces. Faces $ABC$ and $BCD$ of a tetrahedron $ABCD$ meet at an angle of $\pi/6$. The area of triangle $\triangle ABC$ is $120$. The area of triangle $\triangle BCD$ is $80$, and $BC = 10$. What is the volume of the tetrahedron? We call the volume of a tetrahedron as one-third the area of it's base times it's height.

samiul_samin
Posts:1007
Joined:Sat Dec 09, 2017 1:32 pm

Re: BdMO National Secondary 2015#5

Unread post by samiul_samin » Wed Feb 20, 2019 10:23 pm

Hint
$V=\dfrac 13×b×h$
Answer
$320$
Solution source

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