BdMO National Higher Secondary 2019/3

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samiul_samin
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BdMO National Higher Secondary 2019/3

Unread post by samiul_samin » Mon Mar 04, 2019 9:13 am

Let $\alpha$ and $\omega$ be two circles such that $\omega$ goes through the center of $\alpha$.$\omega$ intersects $\alpha$ at $A$ and $B$.Let $P$ any point on the circumference $\omega$.The lines $PA$ and $PB$ intersects $\alpha$ again at $E$ and $F$ respectively.Prove that $AB=EF$.

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