BdMO National Junior 2020 P3

Discussion on Bangladesh Mathematical Olympiad (BdMO) National
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Mursalin
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BdMO National Junior 2020 P3

Unread post by Mursalin » Thu Feb 04, 2021 12:19 am

পায়েলের কাছে দুইটি \(20\) তল বিশিষ্ট ছক্কা আছে। সে ছক্কা দুইটি চালে এবং চালের যোগফল নেয়। কোন সংখ্যাটি আসার সম্ভাবনা সব থেকে বেশি?

(একটি \(20\) তল বিশিষ্ট ছক্কা হচ্ছে একটি পলিহেড্রন বা বহুতলক (ত্রিমাত্রিক বস্তু) যার \(20\) টি তল রয়েছে যেখানে তলগুলোতে \(1\) থেকে \(20\) পর্যন্ত সংখ্যা লেখা রয়েছে। প্রতি চালে প্রতিটি সংখ্যা উঠার সম্ভাবনা সমান)


Payel has two \(20\) sided dice. He rolls them and takes their sum. What number has the highest probability of happening?

(A \(20\) sided die is a polyhedron (a \(3\)d object) with \(20\) faces, with the numbers from \(1\) to \(20\) on them. Each number has an equal probability of coming up on a roll of the die.)
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Zafar
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Re: BdMO National Junior 2020 P3

Unread post by Zafar » Thu Mar 11, 2021 8:20 pm

assume x and y are the two outcomes .
0<x<21 and 0<y<21 .
so ,1< x + y <41
we can move forward like this ,
x + y = sum
>> (x+1)+(y-1)= sum
and finally at a point
>> (x+(y-1))+(y-(y-1)) = sum

so , if we take the minimum x and maximum y , we can get the sum in maximum way .
so ,
20+1=21
(solved :) )

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Mehrab4226
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Location:Dhaka, Bangladesh

Re: BdMO National Junior 2020 P3

Unread post by Mehrab4226 » Sat Mar 13, 2021 12:38 pm

LaTeXed
assume $x$ and $y$ are the two outcomes .
$0<x<21$ and $0<y<21$ .
so ,$1< x + y <41$
we can move forward like this ,
$x + y = sum$
$\Rightarrow (x+1)+(y-1)= sum$
and finally at a point
$\Rightarrow (x+(y-1))+(y-(y-1)) = sum$

so , if we take the minimum $x$ and maximum $y$ , we can get the sum in maximum way .
so ,
$20+1=21 $
(solved :) )
The Mathematician does not study math because it is useful; he studies it because he delights in it, and he delights in it because it is beautiful.
-Henri Poincaré

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