This just shows the use of integration in inequality.
If $f:[a,b] \rightarrow \mathbb R$ is convex then,
\[f(\frac {a+b}{2}) \leq \frac 1 {b-a} \int_a^b f(x)dx \leq \frac {f(a)+f(b)} 2\]
Hermite–Hadamard inequality(BOMC-2011)
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Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi