so that means , as the numbers except $2^k$ type has at least an odd divisor we can do this .*Mahi* wrote:@Tiham:
Add theseTo you solution , and see what you get. It improves the precision.
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nafistiham
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\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.