so that means , as the numbers except $2^k$ type has at least an odd divisor we can do this .*Mahi* wrote:@Tiham:
Add theseTo you solution , and see what you get. It improves the precision.
Advanced P-3(BOMC-2)
- nafistiham
- Posts:829
- Joined:Mon Oct 17, 2011 3:56 pm
- Location:24.758613,90.400161
- Contact:
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.