Page 4 of 4
Re: [OGC1] Online Geometry Camp: Day 4
Posted: Tue Jan 06, 2015 8:57 pm
by *Mahi*
Instead of writing
$Solution$ $of$ $problem$ $6$:
please use
$\text{Solution of problem 6}$
Re: [OGC1] Online Geometry Camp: Day 4
Posted: Tue Jan 06, 2015 9:34 pm
by tanmoy
*Mahi* wrote:Instead of writing
$Solution$ $of$ $problem$ $6$:
please use
$\text{Solution of problem 6}$
Okay,thanks.
Re: [OGC1] Online Geometry Camp: Day 4
Posted: Sat Jan 10, 2015 6:51 pm
by tanmoy
$\text{solution of problem 2}$:
$YP=YA,\therefore \angle YPA=\angle YAP$.Again,$XA=XQ,\therefore \angle XAQ=\angle XQA$.But $\angle PAY=\angle XAQ.\therefore \angle YPX=\angle XQY$.$\therefore$ $PYXQ$ is cyclic.$\therefore$ By $\text{POWER OF POINT}$,$GY=\frac{GP\times GQ}{GX}=\frac{266\times 255}{190}=357$.$\therefore XY=357-190=167$.
