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National Camp 2016
Posted: Mon Feb 20, 2017 4:14 pm
Let ABC be an arbitrary triangle. On the three sides of triangle ABC , three regular n-gons external to the triangle are drawn. Find all values of n for which the centers of the n-gons are vertices of an equilateral triangle.
Re: National Camp 2016
Posted: Mon Sep 25, 2017 3:48 am
If $ABC$ is an arbitrary triangle and the value of $n$ satisfies the given condition,obviously it will be also true for certain $ABC$.Consider a triangle $ABC$ with angle $$A=120$$, $$AB=AC$$, circumcenter $O$, midpoint of $$AB=M$$, midpoint of $$AC=N$$, center of the regular polygon constructed outside of $AB$ is $Z$ and $AC$ is $Y$ and $BC$ is $A$.
for all $n$, $YZ$ is parallel to $MN$ and so triangle $ZYO$ is similar to $MNO$, which is equilateral. Since $X$ belongs to the perpendicular bisector of $BC$, $$X=O$$ and which is possible only then, when $$n=3$$.
So, $$n=3$$ can be one solution and it is($XYZ$ is a Nepoleon triangle).So, there exist exactly one value of $n$ which is $3$.