Math problem 2 (need solution)
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There are three points in a plane[somotol-a].One can draw as many parallelograms as possible keeping those three points as the three vertices of the parallelogram.Find the difference between the area of parallelogram having the largest perimeter possible and the parallelogram having the minimum permeter possible.
I have done it. But I am not sure abt it... So anyone please give me the answer.....
I have done it. But I am not sure abt it... So anyone please give me the answer.....
Ataher Sams
Re: Math problem 2 (need solution)
Try posting your own solution. Then you'll know whether that's right or wrong.
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Nur Muhammad Shafiullah | Mahi
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Re: Math problem 2 (need solution)
How ?ataher.sams wrote:One can draw as many parallelograms as possible keeping those three points as the three vertices of the parallelogram
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Re: Math problem 2 (need solution)
Not actually, you can draw only 3 parallelogram with 3 given vertexes. So if the given points are $A, B,C$ then the answer of your problem is $2\left(\max\{AB,BC,CA\}-\min\{AB,BC,CA\}\right)$
By the way, if you want to post something drawn, you can draw it in your PC and then submit it as a attachment.
By the way, if you want to post something drawn, you can draw it in your PC and then submit it as a attachment.
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Re: Math problem 2 (need solution)
@Corei13:Corei13 wrote:Not actually, you can draw only 3 parallelogram with 3 given vertexes. So if the given points are $A, B,C$ then the answer of your problem is $2\left(\max\{AB,BC,CA\}-\min\{AB,BC,CA\}\right)$
You can see this topic.
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Re: Math problem 2 (need solution)
Please Install $L^AT_EX$ fonts in your PC for better looking equations,
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Re: Math problem 2 (need solution)
any three vertices of a parallellogram make a triangle having half the area of it.and, the other vertex is such a point that creates another triangle having a common side with the previous one.these triangles are congruent.so the answer is $0$
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: Math problem 2 (need solution)
I misread as it asked the difference between maximum and minimum perimeter. Actually $2\left(\max\{AB,BC,CA\}-\min\{AB,BC,CA\}\right)$ doesn't express an area here!
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