\[2^{x-1}+2^{x+1} = 320\]
Can anyone please show me the process...
SOLVE IT ...
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Ataher Sams
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Re: SOLVE IT ...
well, this is kind of text book type question from IX-X
\[2^{x+1}+2^{x-1}=320\]
\[\Rightarrow 2^{x}\left ( 2+\frac{1}{2} \right )=320\]
\[2^{x+1}+2^{x-1}=320\]
\[\Rightarrow 2^{x}\left ( 2+\frac{1}{2} \right )=320\]
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.