\[sinx+sin(2x)+sin(2^2x)+sin(2^3x)....+sin(2^{2n+1}x)=0\]
If $x>0$ & $n>1$ ,Then find the value of $x$.
Mysterious(self-made)
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Last edited by sakibtanvir on Thu Jan 26, 2012 12:24 pm, edited 6 times in total.
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- nafistiham
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Re: Mysterious(self-made)
i think you missed a $2$ heresakibtanvir wrote:1.\[+sin\alpha 2^3..................+sin\alpha^{2n+1}=0\]
and, as $sin0=0$
for $\alpha=\beta=0$
there can be any $n,r$
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
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Re: Mysterious(self-made)
Thanks to remind me....now it is edited and find the answer with new given series.(If it was like that i would not call it self made....i would call MORON MADE. )
Last edited by sakibtanvir on Wed Jan 25, 2012 4:58 pm, edited 1 time in total.
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.
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Re: Mysterious(self-made)
Hint:Get out of of this theta thing......
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Re: Mysterious(self-made)
Need more edition.We need exact value of $n$.
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- nafistiham
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Re: Mysterious(self-made)
of course, without defining any of $n,\beta$, we can't define the other.can we
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.
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Re: Mysterious(self-made)
What about,\[sin120^{\circ}\]
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.