I need help

[Thanic Nur Samin]

I can't solve this one.
Given the value of $a$ and $b$,where $AA'CBB'$ is a thread, is there any formula such that
$x=f(a,b)$?
Sorry I am a little amateur in paint.

[Raiyan Jamil]

I'm not sure, but I think there isn't. Suppose that in the above structure that you gave, the value of x is increased by a bit. By that, the thread will eventually rise up having change in the value of 'a'. But if the length of the thread is increased, it will come down and eventually the value of a will remain the same at that point. For this I think there isn't any formula. But I can't tell it surely.