a trigonometry problem
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If $m^2-n^2=16mn$ and $tanß+sinß=m$,then prove that $tanß-sinß=n$.
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Re: a trigonometry problem
I am confused about the question .Why this $"\beta"$ angle is a variable when the equations tell,
$\displaystyle \sin \beta = \pm \sqrt {\frac{-1 \pm \sqrt {65}}{32}}$.But if the complex angles(!) are not allowed,then,
$\displaystyle \sin \beta = \pm \sqrt{\frac{-1+ \sqrt {65}}{32}}$.
$\displaystyle \sin \beta = \pm \sqrt {\frac{-1 \pm \sqrt {65}}{32}}$.But if the complex angles(!) are not allowed,then,
$\displaystyle \sin \beta = \pm \sqrt{\frac{-1+ \sqrt {65}}{32}}$.
An amount of certain opposition is a great help to a man.Kites rise against,not with,the wind.
Re: a trigonometry problem
I think the following assertion is correct to be proved:
If $m^2-n^2=4\sqrt {mn}$ and $m=\tan \beta+\sin \beta$,then show that $n=\tan \beta-\sin \beta$.
If $m^2-n^2=4\sqrt {mn}$ and $m=\tan \beta+\sin \beta$,then show that $n=\tan \beta-\sin \beta$.
Last edited by *Mahi* on Sun Oct 21, 2012 9:49 pm, edited 1 time in total.
Reason: Typo fixed
Reason: Typo fixed
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