If $e=\frac{a}{b}=\frac{c}{d}$, where $b>d$ and $a>c$ prove that $e=\frac{a-c}{b-d}$
I know it is true but have failed to prove it. Can someone pull me out of this misery please?
Number Theory Proof please
- Fahim Shahriar
- Posts:138
- Joined:Sun Dec 18, 2011 12:53 pm
Re: Number Theory Proof please
$a=be$ and $c=de$
$\frac {a-c}{b-d} = \frac {be-de}{b-d} = \frac {e(b-d)}{b-d} = e$
$\frac {a-c}{b-d} = \frac {be-de}{b-d} = \frac {e(b-d)}{b-d} = e$
Name: Fahim Shahriar Shakkhor
Notre Dame College
Notre Dame College