BdMO 2017 Dhaka divitional

 Posts: 21
 Joined: Sat Jan 28, 2017 11:06 pm
BdMO 2017 Dhaka divitional
The $‘energy’$ of an ordered triple $(a,b,c)$ formed by three positive integers $a,b,c$ is said to be $n$, if the following ${a}\leq{b}\leq{c}, gcd(a,b,c)=1$ and $(a^n+b^n+c^n)$ is divisible by $(a+b+c)$. There are some possible ordered triple whose $‘energy’$ can be of all values of ${n}\geq{1}$ In that case, for what is the maximum value of $(a+b+c)$?
 samiul_samin
 Posts: 999
 Joined: Sat Dec 09, 2017 1:32 pm
Re: BdMO 2017 Dhaka divitional
This problem was posted before in this forum but no solution was given.
 samiul_samin
 Posts: 999
 Joined: Sat Dec 09, 2017 1:32 pm
Re: BdMO 2017 Dhaka divitional
Answer:$3$soyeb pervez jim wrote: ↑Wed Mar 28, 2018 8:02 pmThe energy of an ordered triple $(a,b,c)$ formed by three positive integers $a,b,c$ is said to be $n$, if the following ${a}\leq{b}\leq{c}, gcd(a,b,c)=1$ and $(a^n+b^n+c^n)$ is divisible by $(a+b+c)$. There are some possible ordered triple whose $‘energy’$ can be of all values of ${n}\geq{1}$ In that case, for what is the maximum value of $(a+b+c)$?
Only one solution and $a=b=c=1$