Someone ans it.
Imagine you have $5$ green and $5$ blue balls in a box. 2 balls are taken from the box what is the probability of at least one ball will be blue. What is the probability of those two balls will green
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Re: Someone ans it.
Probablity of at least $1$ ball is blue=$\dfrac{\dbinom{5}{1}×\dbinom {5}{1}+\dbinom {5}{2}x\dbinom {5}{0}
}{\dbinom {10}{2}}=\dfrac 79$
Probablity of $2$ ball is green=$\dfrac{\dbinom {5}{2}×\dbinom{5}{0}}{\dbinom {10}{2}}=\dfrac 29$
}{\dbinom {10}{2}}=\dfrac 79$
Probablity of $2$ ball is green=$\dfrac{\dbinom {5}{2}×\dbinom{5}{0}}{\dbinom {10}{2}}=\dfrac 29$