Yeah, that's not any joke! I'm really gonna prove that!
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
0^0=1!
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Re: 0^0=1!
I found this topic explained .
Go to-https://brilliant.org/wiki/what-is-00/
Go to-https://brilliant.org/wiki/what-is-00/
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