Factorial
Need the proof of 0!=1
Re: Factorial
There is no proof, it's a definition.
Re: Factorial
একটা বস্তুর মধ্য থেকে একটা বস্তু একভাবেই নেয়া যায়। এবার সমাবেশ এর সুত্র ব্যবহার করে দেখ।
হার জিত চিরদিন থাকবেই
তবুও এগিয়ে যেতে হবে.........
বাধা-বিঘ্ন না পেরিয়ে
বড় হয়েছে কে কবে.........
তবুও এগিয়ে যেতে হবে.........
বাধা-বিঘ্ন না পেরিয়ে
বড় হয়েছে কে কবে.........
Re: Factorial
my teacher once gave me that Proof( not by me0,
$n! =n(n-1)!$
Or,$(n-1)! = n(n-1)!/n =n!/n$
Putting n = 1, we have
$O! = 1!/1=1$
$n! =n(n-1)!$
Or,$(n-1)! = n(n-1)!/n =n!/n$
Putting n = 1, we have
$O! = 1!/1=1$
Try not to become a man of success but rather to become a man of value.-Albert Einstein
Re: Factorial
Here you need to define $1!$ first. This is also acceptable. But usually $0!$ is defined first then all the other positive integer factorials are derived from it.photon wrote:my teacher once gave me that Proof( not by me0,
$n! =n(n-1)!$
Or,$(n-1)! = n(n-1)!/n =n!/n$
Putting n = 1, we have
$O! = 1!/1=1$
-
- Posts:35
- Joined:Wed Mar 16, 2011 12:30 pm
- Location:Dhaka
Re: Factorial
actually n things can be per mutated by n! if n is zero there is only one way to permute and it is i cannot permute. so 0!=1
Re: Factorial
No, that's not a good definition. Because,
$n! = (n-1)! * n$ where $n > 0$ and one initial value. Usually the initial value is taken as $0! = 1$. But you can take any initial value.
does not mean anything until you have defined what $n!$ is. So you need to define factorial first. Which is done by,raihan khan wrote:n things can be per mutated by n!
$n! = (n-1)! * n$ where $n > 0$ and one initial value. Usually the initial value is taken as $0! = 1$. But you can take any initial value.