I have determined the maximum area of the triangle (221√3 - 400).But the matter of irony is that the area isn't in the form as mentioned in the question.
![Sad :(](./images/smilies/icon_e_sad.gif)
What is the question number?mizan_24 wrote: ↑Mon Dec 24, 2018 12:56 pmThe lengths of the sides of the rectangle $ABCD$ are $10$ and $11$. An equilateral triangle is drawn in such a way that no point is situated outside ABCD. The maximum area of the triangle can be expressed as $\dfrac{p\sqrt q}{r}$ [where $p, q$ and $r$ are positive integers and $q$ is not divisible by any square number. $p+q+r=?$
I have determined the maximum area of the triangle $(221\sqrt 3 - 400)$.But the matter of irony is that the area isn't in the form as mentioned in the question.![]()