Chittagong-Higher secondary 2016

For students of class 11-12 (age 16+)
mizan_24
Posts: 1
Joined: Mon Dec 24, 2018 12:37 pm

Chittagong-Higher secondary 2016

Unread post by mizan_24 » Mon Dec 24, 2018 12:56 pm

The lengths of the sides of the rectangle ABCD are 10 and 11. An equilateral triangle is drawn in such a way that no point is situated outside ABCD. The maximum area of the triangle can be expressed as (p√q)/r where p, q and r are positive integers and q is not divisible by any square number. p+q+r=?


I have determined the maximum area of the triangle (221√3 - 400).But the matter of irony is that the area isn't in the form as mentioned in the question. :(

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samiul_samin
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Joined: Sat Dec 09, 2017 1:32 pm

Re: Chittagong-Higher secondary 2016

Unread post by samiul_samin » Mon Feb 18, 2019 4:28 pm

mizan_24 wrote:
Mon Dec 24, 2018 12:56 pm
The lengths of the sides of the rectangle $ABCD$ are $10$ and $11$. An equilateral triangle is drawn in such a way that no point is situated outside ABCD. The maximum area of the triangle can be expressed as $\dfrac{p\sqrt q}{r}$ [where $p, q$ and $r$ are positive integers and $q$ is not divisible by any square number. $p+q+r=?$


I have determined the maximum area of the triangle $(221\sqrt 3 - 400)$.But the matter of irony is that the area isn't in the form as mentioned in the question. :(
What is the question number?

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