GEOMETRY MARATHON: SEASON 2
Posted: Fri Sep 16, 2011 8:23 pm
I guess it's time to restart Geometry Marathon.
RULES: Very simple. I'll start this Marathon with a geometry problem. Next who can give the solution of the problem, will get a chance to post a new problem. Different solutions are welcome too. Who will give a different solution also can get a chance to post a new problem. To make things interesting, one have to post solution of a problem within 12 hours. After 12 hours, the problem will be a star problem and the problem will be re-posted in a new topic. But the Geometry Marathon will be continued by posting a new problem from the former solvers....
Hope u will enjoy the Geometry Marathon.
Problem 1:
Let $O$ be the circumcentre of an acute-angled triangle $ABC$. A line through $O$ intersects
the sides $CA$ and $CB$ at points $D$ and $E$ respectively, and meets the circumcircle of
triangle $ABO$ again at point $P$ (Not $O$) inside the triangle. A point $Q$ on side $AB$ is such
that $AQ/QB = DP/PE$
Prove that $\angle APQ = 2\angle CAP$
RULES: Very simple. I'll start this Marathon with a geometry problem. Next who can give the solution of the problem, will get a chance to post a new problem. Different solutions are welcome too. Who will give a different solution also can get a chance to post a new problem. To make things interesting, one have to post solution of a problem within 12 hours. After 12 hours, the problem will be a star problem and the problem will be re-posted in a new topic. But the Geometry Marathon will be continued by posting a new problem from the former solvers....
Hope u will enjoy the Geometry Marathon.
Problem 1:
Let $O$ be the circumcentre of an acute-angled triangle $ABC$. A line through $O$ intersects
the sides $CA$ and $CB$ at points $D$ and $E$ respectively, and meets the circumcircle of
triangle $ABO$ again at point $P$ (Not $O$) inside the triangle. A point $Q$ on side $AB$ is such
that $AQ/QB = DP/PE$
Prove that $\angle APQ = 2\angle CAP$