$ABCDEF$ is a cyclic hexagon with $AB=BC=CD=DE$. $K$ is a point on segment $AE$ satisfying $\angle BKC=\angle KFE$, $\angle CKD=\angle KFA.$
Prove that $KC=KF$
China TST 2016 P1
- Kazi_Zareer
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We cannot solve our problems with the same thinking we used when we create them.
- nahin munkar
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Re: China TST 2016 P1
Use $ homotety$.It may be a useful way to get the solution.
# Mathematicians stand on each other's shoulders. ~ Carl Friedrich Gauss
- Kazi_Zareer
- Posts:86
- Joined:Thu Aug 20, 2015 7:11 pm
- Location:Malibagh,Dhaka-1217
Re: China TST 2016 P1
Did you solve it?nahin munkar wrote:Use $ homotety$.It may be a useful way to get the solution.
We cannot solve our problems with the same thinking we used when we create them.
- nahin munkar
- Posts:81
- Joined:Mon Aug 17, 2015 6:51 pm
- Location:banasree,dhaka
Re: China TST 2016 P1
Yeah, solved.Kazi_Zareer wrote:Did you solve it?nahin munkar wrote:Use $ homotety$.It may be a useful way to get the solution.
# Mathematicians stand on each other's shoulders. ~ Carl Friedrich Gauss