CGMO 2007/5
- Ananya Promi
- Posts:36
- Joined:Sun Jan 10, 2016 4:07 pm
- Location:Naogaon, Bangladesh
Point $D$ lies inside triangle $ABC$ such that $$\angle{DAC}=\angle{DCA}=30^o$$ and $$\angle{DBA}=60^o$$. Point $E$ is the midpoint of segment $BC$. Point $F$ lies on segment $AC$ with $AF=2FC$. Prove that $DE$ I $EF$.
- Atonu Roy Chowdhury
- Posts:64
- Joined:Fri Aug 05, 2016 7:57 pm
- Location:Chittagong, Bangladesh