Hard geo?
- Ananya Promi
- Posts:36
- Joined:Sun Jan 10, 2016 4:07 pm
- Location:Naogaon, Bangladesh
$ABCDEF$ is a convex hexagon inscribed in a circle so that the diagonals $AD, BE$ and $CF$ are concurrent at $J$ and $$\angle{AJB}=\angle{BJC}=60^o$$. Prove that, $AJ+CJ+EJ=BJ+DJ+FJ$.