Prime divisors of form $4k+3$
- Thanic Nur Samin
- Posts:176
- Joined:Sun Dec 01, 2013 11:02 am
Let $m$ be a positive integer. Prove that the sequence $\{a_n\}=2^nm+1$ contains infinitely many prime divisors of the form $4k+3$.
Hammer with tact.
Because destroying everything mindlessly isn't cool enough.
Because destroying everything mindlessly isn't cool enough.
Re: Prime divisors of form $4k+3$
Can m be any positive integer?
- Thanic Nur Samin
- Posts:176
- Joined:Sun Dec 01, 2013 11:02 am
Re: Prime divisors of form $4k+3$
$m$ is a fixed positive integer. So yes, it can be any positive integer.Someone wrote:Can m be any positive integer?
Hammer with tact.
Because destroying everything mindlessly isn't cool enough.
Because destroying everything mindlessly isn't cool enough.
- Thanic Nur Samin
- Posts:176
- Joined:Sun Dec 01, 2013 11:02 am
Re: Prime divisors of form $4k+3$
Hammer with tact.
Because destroying everything mindlessly isn't cool enough.
Because destroying everything mindlessly isn't cool enough.