$f(x)=\sqrt{x^2+1}$
$f(g(x))=3|x|$
Then $g(x)=?$
Function problem
Re: Function problem
Let $f^{-1}(x)=y$, then $f(f^{-1}(x))=f(y)=\sqrt{y^2+1}=x$ which implies $y=\pm \sqrt{x^2-1}$. So $g(x)=f^{-1}(3|x|)=\pm\sqrt{9x^2-1}$.
- What is the value of the contour integral around Western Europe?
- Zero.
- Why?
- Because all the poles are in Eastern Europe.
Revive the IMO marathon.
- Zero.
- Why?
- Because all the poles are in Eastern Europe.
Revive the IMO marathon.