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a+b+c>=1/a+1/b+1/c

Posted: Sat Jul 01, 2017 3:31 pm
by Katy729
Let $a,b,c$ be positive real numbers, such that: $a+b+c \geq \frac{1}{a}+\frac{1}{b}+\frac{1}{c}.$

Prove that:
\[a+b+c \geq \frac{3}{a+b+c}+\frac{2}{abc}. \]

Re: a+b+c>=1/a+1/b+1/c

Posted: Wed Sep 06, 2017 6:02 pm
by Katy729
Someone? :(

Re: a+b+c>=1/a+1/b+1/c

Posted: Sat Apr 21, 2018 10:55 pm
by Katy729
Someone? Pleasee :(

Re: a+b+c>=1/a+1/b+1/c

Posted: Thu Nov 22, 2018 9:34 pm
by Katy729
Please someone... :(