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### 0^0=1!

Posted: Wed Apr 24, 2019 4:57 pm
Yeah, that's not any joke! I'm really gonna prove that!
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.

### Re: 0^0=1!

Posted: Thu May 16, 2019 10:36 am
SINAN EXPERT wrote:
Wed Apr 24, 2019 4:57 pm
Yeah, that's not any joke! I'm really gonna prove that!
We know, $2^6=64$
Again, $2^6=(2+0)^6=6_{C_0}2^60^0+6_{C_1}2^50^1+6_{C_2}2^40^2+...=64*0^0$ $⇒64=64*0^0$
Which is a clear proof of $0^0=1$.
True to say, I haven't found any mistake here.
Why $64\times 0^0=64$?

### Re: 0^0=1!

Posted: Sat May 18, 2019 5:54 pm
samiul_samin wrote:
Thu May 16, 2019 10:36 am
Why $64\times 0^0=64$?
$2^6=(2+0)^6⇒64=64*0^0$

### Re: 0^0=1!

Posted: Thu Aug 15, 2019 10:42 pm
Give some logic. It's still not clear