AIME 1999

For discussing Olympiad Level Combinatorics problems
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tanmoy
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Joined:Fri Oct 18, 2013 11:56 pm
Location:Rangpur,Bangladesh
AIME 1999

Unread post by tanmoy » Tue Mar 03, 2015 2:14 pm

Fourty teams play a tournament in which every team plays every other team exactly once.No ties occur,and each team has a $50%$ chance of winning any game that it plays.What is the probability that no two teams win the same number of games :?:
"Questions we can't answer are far better than answers we can't question"
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Tahmid
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Joined:Wed Mar 20, 2013 10:50 pm

Re: AIME 1999

Unread post by Tahmid » Tue Mar 03, 2015 7:26 pm

$\dfrac{40!}{2^{780}}$
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tanmoy
Posts:312
Joined:Fri Oct 18, 2013 11:56 pm
Location:Rangpur,Bangladesh

Re: AIME 1999

Unread post by tanmoy » Tue Mar 03, 2015 10:27 pm

Tahmid wrote:$\frac{40!}{2^{780}}$
I have got the same answer.:D
"Questions we can't answer are far better than answers we can't question"
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Tahmid
Posts:110
Joined:Wed Mar 20, 2013 10:50 pm

Re: AIME 1999

Unread post by Tahmid » Tue Mar 03, 2015 11:45 pm

tanmoy wrote: I have got the same answer.:D
actually everyone will get the same answer ;) ;)
but the problem makes confusion because of its description.
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