In how many ways you can keep $10$ people in $5$ rooms?
Re: Keeping people in the rooms!
Posted: Mon Feb 19, 2018 1:31 pm
by samiul_samin
Solved this in my own. Hint
Use Ball in urn formula
Answer
$\fbox{10!× 126}$
Problem Source
'বিজ্ঞানচিন্তা' January 2018
Solution
Let the peoples are $10$ different types of ball and the rooms are $5$ same urns
Using Ball and urn formula
We can put 10 identical ball in 5 urn $\dbinom 94=126$ ways
If they all are different balls then they can be permuted in $10!$ ways.
So,the total ways of permutation is $\fbox {10!×126}$
The answer is $\fbox {10!×126}$