## a bunch of questions about bonds

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nafistiham
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### a bunch of questions about bonds

1.which is stronger ? covalent bond or ionic bond ?

actually, in our text book it is said without hesitation that ionic bonds are stronger.but, i am not sure whether it is said about the bonds inter molecular force or the bond among the atoms of different elements?

2.when we call a bond covalent or ionic what we see first ? the elements of the bond or the specifications

because, sometimes a bond between a metal and a non metal is called covalent for its specifications

3.what is the cause of a compound or element's molding capability?

we can mold a metal but a non metal breaks so easily.
$\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0$
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Ipsc palash
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### Re: a bunch of questions about bonds

অধাতুর বন্ধন তো সমজোযী. যেমন H . ধাতুর মানে ধাতব বন্ধন কি ধরনের? আমাদের বইয়ে তো উল্লেখ নাই. সকল ধাতুই তো ইলেকট্রন ত্যাগ করে.

Ipsc palash
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### Re: a bunch of questions about bonds

ধাতব বন্ধন নিজেই আলাদা বন্ধন

sowmitra
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### Re: a bunch of questions about bonds

Tiham, you're question was, which bond is stronger-ionic or covalent ? The answer is (without any doubt) - covalent bond. I will provide logic behind my stand. I actually discovered it along with one of my friends. As you know, Ionic Bond is the bond formed from electrostatic force of attraction, and, Covalent Bond is formed from the sharing of electrons. It is very important to distinguish that, in an Ionic Compound all the atoms (correctly-ions) of the individual elements are bound together by ionic bond. On the other hand, in a Covalent Compound, the atoms are attached to one another,inside the moecules, by covalent bond, but, each of the individual molecules are bound together by a much weaker force named Van-der-Waal's Force. It is crucial to notice that, in an ionic compound, a single force-i.e, the electrostatic force force, keeps everything together, whereas, in a covalent compound the total job is done by two forces.
Now that the basics are over, we can find the answer to your question. When we heat water and vaporize it, we are actually breaking up the much weaker Van-der-Waal's force, but, we can never generate enough heat to break the covalent bond inside the molecules. So, the water molecules always remain intact. But, when we heat ionic compounds, we can evidently generate enough heat to break the ionic bonds among the ions in the compound (although the amount of this heat energy is far greater than the amount required to break the Van-der-Waal's force). Therefore, the amount of energy required to break the Ionic Bond is greater than that required to break the Van-der-Waal's force. And since we have not been able to break the covalent bond between molecules by applying heat, in order to break covalent bond we MUST need even more energy than that required to break Ionic Bond.
So, we can conclude that, on the basis of strength,
Van-der-Waal's force<Ionic Bond(Electrostatic Force)<Covalent Bond
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sowmitra
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### Re: a bunch of questions about bonds

Well, Tiham, this theory also suggests that if we could find a substance which is only held together by Covalent Bonds, then, it would have a very high meling point. We all know such a compound-DIAMOND, which is a bunch of carbon atoms held together by nothing except Covalent Bonds. And, it is known to everyone that, the melting point of Diamond is far greater than any ionic compound on this Earth. So, there you go! Solid proof that Covalent Bonds are stronger than Ionic Bonds. (I am happy because I could finally finish this post )
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sourav das
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### Re: a bunch of questions about bonds

Actually first you have to define in basis of which properties you want to compare the strength of these two bonds. I think then we can compare the two bonds more specifically...
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nafistiham
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### Re: a bunch of questions about bonds

সউমিত্র কে অনেক ধন্যবাদ আমাকে আরও পরিষ্কার করে বুঝানোর জন্যে ।
আসলে আমাদের বইয়ে বলা হয়েছিল । তড়িৎযোজী বন্ধনের আন্ত আণবিক শক্তি বেশি । আমি এ কারনেই আমি দ্বিধান্বিত ছিলাম । নিঃসন্দেহে সমযোজী আন্ত পারমাণবিক বন্ধন বেশি শক্তিশালী ।
$\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0$
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.