Divisional MO-2015 (Kushtia) Junior P-10

Problem for Junior Group from Divisional Mathematical Olympiad will be solved here.
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Kazi_Zareer
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Location: Malibagh,Dhaka-1217

Divisional MO-2015 (Kushtia) Junior P-10

Unread post by Kazi_Zareer » Fri Dec 18, 2015 12:24 am

প্যাসকেল সাহেব তার গুন করার সুবিধার জন্য একটি কম্পিউটার তৈরি করেছেন যার নাম দিয়েছেন "রামানুজান​" । কিন্তু রামানুজান (3,5), (2,4), (3,4) এবং (4,7) কে গুণ করে যথাক্রমে 17, 10, 14 এবং 34 বানায়। রামানুজান (5,6) কে গুণ করে কত বানাবে?

MR. Pascal built a computer for multiplying numbers and Named it "Ramanujan". But Ramanujan multiplies (3,5), (2,4), (3,4) and (4,7) and results are 17, 10, 14 and 34. If Ramanujan multiplies (5,6) , What will be the result?
We cannot solve our problems with the same thinking we used when we create them.

Ipshita
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Re: Divisional MO-2015 (Kushtia) Junior P-10

Unread post by Ipshita » Sun Dec 20, 2015 9:33 pm

32.
5*6=30 and 30+2=32.

in every case, 2 is added with the product of the given numbers by "ramanujan'.

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Kazi_Zareer
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Re: Divisional MO-2015 (Kushtia) Junior P-10

Unread post by Kazi_Zareer » Sat Jan 09, 2016 7:13 pm

I think you didn't notice that the computer "Ramanujan", when multiplies $(4,7)$ then the result is $34.$

By the by, the answer is $36$. After multiplying, the computer converts the results in $8-base$ number.
You can see that $3*5=15$. In, 8-base number, it'll be $17$.You can check for others multiplies.

Finally, $5*6 =30$. Thus it is $36$ in $8-base$ number.
We cannot solve our problems with the same thinking we used when we create them.

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