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Divisional MO-2015 (Kushtia) Junior P-10

Posted: Fri Dec 18, 2015 12:24 am
by Kazi_Zareer
প্যাসকেল সাহেব তার গুন করার সুবিধার জন্য একটি কম্পিউটার তৈরি করেছেন যার নাম দিয়েছেন "রামানুজান​" । কিন্তু রামানুজান (3,5), (2,4), (3,4) এবং (4,7) কে গুণ করে যথাক্রমে 17, 10, 14 এবং 34 বানায়। রামানুজান (5,6) কে গুণ করে কত বানাবে?

MR. Pascal built a computer for multiplying numbers and Named it "Ramanujan". But Ramanujan multiplies (3,5), (2,4), (3,4) and (4,7) and results are 17, 10, 14 and 34. If Ramanujan multiplies (5,6) , What will be the result?

Re: Divisional MO-2015 (Kushtia) Junior P-10

Posted: Sun Dec 20, 2015 9:33 pm
by Ipshita
32.
5*6=30 and 30+2=32.

in every case, 2 is added with the product of the given numbers by "ramanujan'.

Re: Divisional MO-2015 (Kushtia) Junior P-10

Posted: Sat Jan 09, 2016 7:13 pm
by Kazi_Zareer
I think you didn't notice that the computer "Ramanujan", when multiplies $(4,7)$ then the result is $34.$

By the by, the answer is $36$. After multiplying, the computer converts the results in $8-base$ number.
You can see that $3*5=15$. In, 8-base number, it'll be $17$.You can check for others multiplies.

Finally, $5*6 =30$. Thus it is $36$ in $8-base$ number.