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Dhaka Junior 2011/7

Posted: Tue Feb 01, 2011 8:04 pm
by ahmedulkavi
A four headed giant has $63$ children. He wants to name them. The names should be in three English letters. A letter can be used more than one time but the names shouldn't be same. What is the least number of the letters
used in the names?

Re: Divitional math olympyad 2011

Posted: Tue Feb 01, 2011 11:34 pm
by Moon
Almost same problem appeared in Secondary category: viewtopic.php?f=41&t=478
Answer:
$4$ as $4^3=64>63$ :)

Re: Dhaka Junior 2011/7

Posted: Fri Apr 29, 2011 12:29 am
by tarek like math
Answer=4 total different names=64
A,B=6 A=1
A,C=6 B=1
B,C=6 C=1
A,D=6 D=1
B,D=6
C,D=6
ABC=6 ABD=6 ACD=6 BCD=6