Dhaka Junior 2011/6
Forum rules
Please don't post problems (by starting a topic) in the "Junior: Solved" forum. This forum is only for showcasing the problems for the convenience of the users. You can post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Please don't post problems (by starting a topic) in the "Junior: Solved" forum. This forum is only for showcasing the problems for the convenience of the users. You can post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Dhaka Junior 2011/6
6. Each of Rinku, Tiya and Abir are asked to choose three numbers so that the sum of the third and the first number is twice the second one and the third number is $2$ greater than the second number. It was observed that the second number of Rinku is $2$ smaller than the second number of Tiya and the second number of Tiya is $2$ smaller than the second number of Abir. If the third number chosen by Tiya is $15$, find the first number chosen by Abir.
"Inspiration is needed in geometry, just as much as in poetry."  Aleksandr Pushkin
Please install LaTeX fonts in your PC for better looking equations,
learn how to write equations, and don't forget to read Forum Guide and Rules.
Please install LaTeX fonts in your PC for better looking equations,
learn how to write equations, and don't forget to read Forum Guide and Rules.

 Posts: 78
 Joined: Thu Jan 20, 2011 10:46 am
Re: Dhaka Junior 2011/6
The first number chosen by abir is 13

 Posts: 2
 Joined: Sat Dec 10, 2011 1:12 pm
Re: Dhaka Junior 2011/6
but how u get the ans ?
Re: Dhaka Junior 2011/6
CONDITION, X1 + X3 = 2 X2 and X3 = X2 + 2. GIVEN : Xr2 = Xt2 2, Xt2= Xa22, Xt3= 15, Xa1=?
X1 = X2 2,
NOW, FROM 2nd con., Xt2 = 152=13. Xa2= Xt2+2=13+2=15. Xa1= Xa22=152=13.
X1 = X2 2,
NOW, FROM 2nd con., Xt2 = 152=13. Xa2= Xt2+2=13+2=15. Xa1= Xa22=152=13.