Dhaka Junior 2011/6

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Dhaka Junior 2011/6

Unread post by Moon » Wed Feb 02, 2011 8:24 am

6. Each of Rinku, Tiya and Abir are asked to choose three numbers so that the sum of the third and the first number is twice the second one and the third number is $2$ greater than the second number. It was observed that the second number of Rinku is $2$ smaller than the second number of Tiya and the second number of Tiya is $2$ smaller than the second number of Abir. If the third number chosen by Tiya is $15$, find the first number chosen by Abir.
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Mehfuj Zahir
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Re: Dhaka Junior 2011/6

Unread post by Mehfuj Zahir » Wed Feb 02, 2011 11:33 am

The first number chosen by abir is 13

nowshin tasnim
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Re: Dhaka Junior 2011/6

Unread post by nowshin tasnim » Wed Dec 14, 2011 12:15 pm

but how u get the ans ?

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Re: Dhaka Junior 2011/6

Unread post by surjo » Mon Dec 31, 2012 9:47 pm

CONDITION, X1 + X3 = 2 X2 and X3 = X2 + 2. GIVEN : Xr2 = Xt2 -2, Xt2= Xa2-2, Xt3= 15, Xa1=?
X1 = X2 -2,
NOW, FROM 2nd con., Xt2 = 15-2=13. Xa2= Xt2+2=13+2=15. Xa1= Xa2-2=15-2=13.

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