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### Dhaka Junior 2011/9

Posted: Wed Feb 02, 2011 8:27 am
9. \$ABC\$ is a triangle with \$AB = 4\$, \$BC = 5\$ and \$AC = 3\$. \$O\$ is the midpoint of \$BC\$. A line from \$O\$ parallel to \$AC\$ meets \$AB\$ at \$D\$. \$E\$ is on \$DO\$ so that \$DO = OE\$ and \$D\$ and \$E\$ are on opposite sides of \$BC\$. Find \$BE^2\$.

### Re: Dhaka Junior 2011/9

Posted: Wed Feb 02, 2011 11:31 am

### Re: Dhaka Junior 2011/9

Posted: Wed Feb 02, 2011 1:55 pm
How can we get the answer ?

### Re: Dhaka Junior 2011/9

Posted: Wed Feb 02, 2011 2:47 pm

### Re: Dhaka Junior 2011/9

Posted: Wed Jul 11, 2012 8:56 am May be BE=DC.
(BOE and DOC is similar)
DC^2=OC^2-OD^2=2.5^2-1.5^2=4

### Re: Dhaka Junior 2011/9

Posted: Wed Aug 29, 2012 11:48 pm
\$BD=2\$
\$DE=DO+OE=DO+DO=AC=3\$
\$BE^2=BD^2+DE^2=13\$

### Re: Dhaka Junior 2011/9

Posted: Thu Jan 10, 2013 5:10 pm
nafistiham wrote:\$BD=2\$
\$DE=DO+OE=DO+DO=AC=3\$
\$BE^2=BD^2+DE^2=13\$
Can u draw it on a paper and then upload the image with positions of all e points? I cant understand the position of e

### Re: Dhaka Junior 2011/9

Posted: Fri Jan 25, 2013 12:56 pm
Shafin wrote:
nafistiham wrote:\$BD=2\$
\$DE=DO+OE=DO+DO=AC=3\$
\$BE^2=BD^2+DE^2=13\$
Can u draw it on a paper and then upload the image with positions of all e points? I cant understand the position of e
Sorry for being so late.  here is what you wanted. there is something called 'extension' :p
junior 2011-9.png (18.07 KiB) Viewed 2077 times