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Dhaka Higher Secondary 2011/10
Posted: Fri Jan 28, 2011 10:35 pm
by BdMO
A point $P$ is chosen inside a right angled triangle $ABC$, perpendicular lines $PS$, $PQ$ and $PR$ are drawn from $P$ on $AB, BC$ and $AC$. $PR = 1, PQ = 2$ and $PS = 3$ and $\angle RPS = 150^{\circ} $. The length of $ AB$ can be written in the form $x \sqrt y +z$ where $x, y, z$ are integers. Find $ x + y + z$.
Re: Dhaka Higher Secondary 2011/10
Posted: Sun Jan 30, 2011 12:23 pm
by TIUrmi
Re: Dhaka Higher Secondary 2011/10
Posted: Sat Sep 03, 2011 9:23 pm
by ibrahim
I've got 8.
ABC=APC+BPC+BPA
1/2 AB*AC=1/2 AC*1+1/2*2*BC+1/2*3*AB
AB=1+ 2*BC/AC+3*AB/AC
=1+2cos60+3tan60
=1+1+3*(3)^(1/2)
so x+y+z=8
akashe shurjota othe nirobe
Re: Dhaka Higher Secondary 2011/10
Posted: Sat Sep 03, 2011 10:34 pm
by Avik Roy
Ibrahim, it's expected that you use LATEX in this forum
And draw a diagram and you should have the explanation for why your answer is incorrect
Re: Dhaka Higher Secondary 2011/10
Posted: Sat Sep 03, 2011 10:48 pm
by ibrahim
I am using on mobile, so i can't using latex. Plz explain....