Some problems to solve

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Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
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sm.joty
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Re: Some problems to solve

Unread post by sm.joty » Sat Dec 24, 2011 12:29 am

Dipika wrote:Actually (n,1-n) is the solution of the problem 3..
In the divisional math Olympiad it was asked to find out the value of x-y=?
so the answer will be 2n-1
How ?
You need to post full solution. (If you want). :)
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*Mahi*
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Re: Some problems to solve

Unread post by *Mahi* » Sat Dec 24, 2011 12:25 pm

Rafi, the actual solution gives $x+y=1$ or $x=y=-1$ so she is right, $x-y$ can be $2n-1$ for any $n$ (and sometimes a limited values , which depens on the domain of $x,y$).
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Dipika
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Re: Some problems to solve

Unread post by Dipika » Sat Dec 24, 2011 2:34 pm

U r right Mahi..
By the way i noticed today that (1-n,n) are the another solution of the problem..
so now the value is 1-2n...

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Abdul Muntakim Rafi
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Re: Some problems to solve

Unread post by Abdul Muntakim Rafi » Sat Dec 24, 2011 9:50 pm

লাবিব DJ কি বলছে তা আমারো মাথার উপর দিয়া গেছে। :o :shock:

আমার উত্তরঃ
Just think normally... The answer is-
$1.1111111111111111111111111.........................$

If it were base 10 the answer would be approximately $1.2$
But as it is base 2 the next number is the answer... which is $10$
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sm.joty
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Re: Some problems to solve

Unread post by sm.joty » Sun Dec 25, 2011 1:15 am

Dj এর আলোচনা আমারও মাথার ওপর দিয়া গেছে। :( :(
তবে আমার উত্তর আসছে 2
আমি এভাবে চিন্তা করছি, .1 কে আমার লিখি $\frac {1}{10}$,
আবার .01 কে লিখি $\frac {1}{100}$
তাহলে আমরা বাইনারি সংখ্যার ক্ষেত্রে লিখতে পারি, $.1=\frac {1}{2}$, $.01=\frac {1}{4}$ ,$.001=\frac {1}{8}$
তাহলে উত্তর হয় 2.
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তবুও এগিয়ে যেতে হবে.........
বাধা-বিঘ্ন না পেরিয়ে
বড় হয়েছে কে কবে.........

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Abdul Muntakim Rafi
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Re: Some problems to solve

Unread post by Abdul Muntakim Rafi » Sun Dec 25, 2011 2:26 am

$2$ ভিত্তিক সংখায় ০ আর ১ ছাড়া আর কিছু নাই। তাই ২ কখনো উত্তর হবে না।
আর তুমি যে ২ বলতেছ, সেইটারে বাইনারিতে ত্রান্সফরম করলে ১০ আসবে।
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nafistiham
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Re: Some problems to solve

Unread post by nafistiham » Wed Dec 28, 2011 6:55 pm

we just need to transform the sequence into base $10$, find out the summation, and then turn it into binary again.which is obviously $10$.nothing complex in it. ;)
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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