I got x=y= 10. I am confused. x and y are different letters, can they have same value?
Chittagong 2012 Higher secondary
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Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Consider a series with $a_1$=2012 and $a_n$= ${\frac{n}{a_{n-1}}}$.$a_1 $x$ a_2$x$ a_3x......$x$ a_{20}$=$2^{x}$x$ y!$.Find the value of x+y.
I got x=y= 10. I am confused. x and y are different letters, can they have same value?
I got x=y= 10. I am confused. x and y are different letters, can they have same value?
Re: Chittagong 2012 Higher secondary
Being different letters is not enough to prevent $x,y$ to different. Read the question again. Is their any restriction telling that $x,y$ can't be the same?Neblina wrote:Consider a series with $a_1$=2012 and $a_n$= ${\frac{n}{a_{n-1}}}$.$a_1 $x$ a_2$x$ a_3x......$x$ a_{20}$=$2^{x}$x$ y!$.Find the value of x+y.
I got x=y= 10. I am confused. x and y are different letters, can they have same value?
$\color{blue}{\textit{To}} \color{red}{\textit{ problems }} \color{blue}{\textit{I am encountering with-}} \color{green}{\textit{AVADA KEDAVRA!}}$
Re: Chittagong 2012 Higher secondary
Awwww...actually i was not really sure about the fact that "Being different letters is not enough to prevent xy to be same"( i think that's what you meant to say) Thanks for clearing up my confusion.