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chitagong 12th bdmo
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Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
ABCD and EFGH are both squares with side length 4 units and DE=CE.AG=?
Re: chitagong 12th bdmo
Extend $AD$ and $GF$.Suppose,they meet at point $I$.
Now,$GI=6$,$AI=8$.$\therefore$ $AG=\sqrt{6^{2}+8^{2}}=10$
Now,$GI=6$,$AI=8$.$\therefore$ $AG=\sqrt{6^{2}+8^{2}}=10$
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