chitagong 12th bdmo p7
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Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
In triangle ABC, AB & AC intersect side DE of rectangle DBCE at F & G points. FG = 2, triangle ABC's perimeter is double of the perimeter of triangle AFG . If area of triangle ABC is 12 sq units, Then find the area of rectangle DBCE.
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Raiyan Jamil
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- Joined:Fri Mar 29, 2013 3:49 pm
Re: chitagong 12th bdmo p7
The area of triangle DBCE is also 12 sq units.
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Re: chitagong 12th bdmo p7
$F$ and $G$ are the midpoints of sides $AB$ and $AC$ respectively.So,$BC=4$ units.The height of triangle $ABC$ is $6$.
$\therefore$ $BD=CE=3$.$\therefore$ $(DBCE)=12$ square units
$\therefore$ $BD=CE=3$.$\therefore$ $(DBCE)=12$ square units
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