[OGC1] Online Geometry Camp: Day 2
- Samiun Fateeha Ira
- Posts:23
- Joined:Sat Aug 24, 2013 7:08 pm
- Location:Dhaka, Bangladesh
ধরি, $P$ বিন্দু $AD$ এর ওপর এবং $Q$ বিন্দু $BC$ এর ওপর অবস্থিত। $PQ$ রেখাংশ এবং $AC$ কর্ণ পরস্পরকে $O$ বিন্দুতে সমকোণে সমদ্বিখণ্ডিত করে।
$AC^2= AD^2+ DC^2= 25+144=169\Longrightarrow AC= 13$
$AO=6.5$
$\triangle AOP$ ও $\triangle ADC$ এ, $\angle AOP=\angle ADC$, $\angle OAP=\angle DAC$.
সুতরাং, $\triangle AOP$, $\triangle ADC$ ত্রিভুজদ্বয় সদৃশ।
$\dfrac {OP}{DC}=\dfrac {AO}{AD} \Longrightarrow \dfrac {OP} 5= \dfrac {6.5}{12} \Longrightarrow OP= \dfrac {32.5}{12}\approx 5.4$
$AC^2= AD^2+ DC^2= 25+144=169\Longrightarrow AC= 13$
$AO=6.5$
$\triangle AOP$ ও $\triangle ADC$ এ, $\angle AOP=\angle ADC$, $\angle OAP=\angle DAC$.
সুতরাং, $\triangle AOP$, $\triangle ADC$ ত্রিভুজদ্বয় সদৃশ।
$\dfrac {OP}{DC}=\dfrac {AO}{AD} \Longrightarrow \dfrac {OP} 5= \dfrac {6.5}{12} \Longrightarrow OP= \dfrac {32.5}{12}\approx 5.4$
- Samiun Fateeha Ira
- Posts:23
- Joined:Sat Aug 24, 2013 7:08 pm
- Location:Dhaka, Bangladesh
Re: [OGC1] Online Geometry Camp: Day 2
Well, I was also unable to see Bangla texts from Google chrome. but now i can read it browsing Mozilla.
Re: [OGC1] Online Geometry Camp: Day 2
@ Ira
How did you prove this-
PQ রেখাংশ এবং AC কর্ণ পরস্পর O বিন্দুতে সমকোণে সমদিখণ্ডিত হয়।?
How did you prove this-
PQ রেখাংশ এবং AC কর্ণ পরস্পর O বিন্দুতে সমকোণে সমদিখণ্ডিত হয়।?
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Re: [OGC1] Online Geometry Camp: Day 2
ইরা, তোমার সমাধান ঠিক আছে
"Your present circumstances don't determine where you can go; they merely determine where you start." -Nido Qubein
Re: [OGC1] Online Geometry Camp: Day 2
ভাইয়া, APCQ কি রম্বস? কীভাবে?
- Samiun Fateeha Ira
- Posts:23
- Joined:Sat Aug 24, 2013 7:08 pm
- Location:Dhaka, Bangladesh
Re: [OGC1] Online Geometry Camp: Day 2
ওই জে...কাগজ ভাঁজের কথা বলা আছে না, তাই করে পেয়েছি।Neblina wrote:@ Ira
How did you prove this-
PQ রেখাংশ এবং AC কর্ণ পরস্পর O বিন্দুতে সমকোণে সমদিখণ্ডিত হয়।?
Re: [OGC1] Online Geometry Camp: Day 2
আমারও সেম রেজাল্ট এসেছে। আমিও ইরার মত করে করেছি।
- asif e elahi
- Posts:185
- Joined:Mon Aug 05, 2013 12:36 pm
- Location:Sylhet,Bangladesh
Re: [OGC1] Online Geometry Camp: Day 2
Here APCQ is a rhombus.
Re: [OGC1] Online Geometry Camp: Day 2
For some reason, Chrome is setting the default encoding for this site Western rather than Unicode utf-8. It can be fixed in this way https://support.google.com/news/answer/61689?hl=en , but it needs to be done every time after loading a pagenayel wrote:For some weird reason I can't read the Bangla texts either! This has never happened with me before. I can however read it after pressing the 'quote' button.
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Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
Use $L^AT_EX$, It makes our work a lot easier!
Nur Muhammad Shafiullah | Mahi
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- Joined:Sun Aug 25, 2013 10:52 pm
- Location:dinajpur,dhaka,bangladesh
Re: [OGC1] Online Geometry Camp: Day 2
Hello,
Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.
By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.
that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!
Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.
By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.
that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!