## Divisional MO-2015 (Kushtia) Junior P-10

Problem for Junior Group from Divisional Mathematical Olympiad will be solved here.
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Please don't post problems (by starting a topic) in the "Junior: Solved" forum. This forum is only for showcasing the problems for the convenience of the users. You can post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Kazi_Zareer
Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

### Divisional MO-2015 (Kushtia) Junior P-10

প্যাসকেল সাহেব তার গুন করার সুবিধার জন্য একটি কম্পিউটার তৈরি করেছেন যার নাম দিয়েছেন "রামানুজান​" । কিন্তু রামানুজান (3,5), (2,4), (3,4) এবং (4,7) কে গুণ করে যথাক্রমে 17, 10, 14 এবং 34 বানায়। রামানুজান (5,6) কে গুণ করে কত বানাবে?

MR. Pascal built a computer for multiplying numbers and Named it "Ramanujan". But Ramanujan multiplies (3,5), (2,4), (3,4) and (4,7) and results are 17, 10, 14 and 34. If Ramanujan multiplies (5,6) , What will be the result?
We cannot solve our problems with the same thinking we used when we create them.

Ipshita
Posts: 1
Joined: Sun Dec 20, 2015 9:22 pm

### Re: Divisional MO-2015 (Kushtia) Junior P-10

32.
5*6=30 and 30+2=32.

in every case, 2 is added with the product of the given numbers by "ramanujan'.

Kazi_Zareer
Posts: 86
Joined: Thu Aug 20, 2015 7:11 pm
Location: Malibagh,Dhaka-1217

### Re: Divisional MO-2015 (Kushtia) Junior P-10

I think you didn't notice that the computer "Ramanujan", when multiplies \$(4,7)\$ then the result is \$34.\$

By the by, the answer is \$36\$. After multiplying, the computer converts the results in \$8-base\$ number.
You can see that \$3*5=15\$. In, 8-base number, it'll be \$17\$.You can check for others multiplies.

Finally, \$5*6 =30\$. Thus it is \$36\$ in \$8-base\$ number.
We cannot solve our problems with the same thinking we used when we create them.